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311314160551 = 4447449315581
BaseRepresentation
bin1001000011110111100…
…01010001101110100111
31002202120000111221020111
410201323301101232213
520100032411114201
6355003222513451
731330440463222
oct4417361215647
91082500457214
10311314160551
11110033800609
1250402595887
1323483b71574
14110d3a305b9
158170b07b51
hex487bc51ba7

311314160551 has 8 divisors (see below), whose sum is σ = 311473459584. Its totient is φ = 311154910560.

The previous prime is 311314160519. The next prime is 311314160567. The reversal of 311314160551 is 155061413113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 311314160551 - 25 = 311314160519 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311314160851) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19972581 + ... + 19988161.

It is an arithmetic number, because the mean of its divisors is an integer number (38934182448).

Almost surely, 2311314160551 is an apocalyptic number.

311314160551 is a deficient number, since it is larger than the sum of its proper divisors (159299033).

311314160551 is a wasteful number, since it uses less digits than its factorization.

311314160551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24521.

The product of its (nonzero) digits is 5400, while the sum is 31.

Adding to 311314160551 its reverse (155061413113), we get a palindrome (466375573664).

The spelling of 311314160551 in words is "three hundred eleven billion, three hundred fourteen million, one hundred sixty thousand, five hundred fifty-one".

Divisors: 1 4447 4493 15581 19980371 69288707 70005433 311314160551