Base | Representation |
---|---|
bin | 100011011001000110111110… |
… | …1001000111001011100010001 |
3 | 1111211021100101211200022211221 |
4 | 1012302031331020321130101 |
5 | 311301033002241003101 |
6 | 3022035435304205041 |
7 | 122400465302622343 |
oct | 10662157510713421 |
9 | 1454240354608757 |
10 | 311314214000401 |
11 | 902156869495a7 |
12 | 2aaba944469781 |
13 | 10492a5c3b32a1 |
14 | 56c398cbb1293 |
15 | 25ecee54ccaa1 |
hex | 11b237d239711 |
311314214000401 has 16 divisors (see below), whose sum is σ = 329792883967296. Its totient is φ = 292854031658496.
The previous prime is 311314214000357. The next prime is 311314214000423. The reversal of 311314214000401 is 104000412413113.
It is a cyclic number.
It is not a de Polignac number, because 311314214000401 - 221 = 311314211903249 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (311314214000701) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 282219010 + ... + 283319956.
It is an arithmetic number, because the mean of its divisors is an integer number (20612055247956).
Almost surely, 2311314214000401 is an apocalyptic number.
It is an amenable number.
311314214000401 is a deficient number, since it is larger than the sum of its proper divisors (18478669966895).
311314214000401 is a wasteful number, since it uses less digits than its factorization.
311314214000401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1109328.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 311314214000401 its reverse (104000412413113), we get a palindrome (415314626413514).
The spelling of 311314214000401 in words is "three hundred eleven trillion, three hundred fourteen billion, two hundred fourteen million, four hundred one", and thus it is an aban number.
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