311320000311 has 4 divisors (see below), whose sum is σ = 415093333752. Its totient is φ = 207546666872.

The previous prime is 311320000289. The next prime is 311320000339. The reversal of 311320000311 is 113000023113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 113000023113 = 3 ⋅37666674371.

It is a cyclic number.

It is not a de Polignac number, because 311320000311 - 2¹³ = 311319992119 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311320000391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51886666716 + ... + 51886666721.

It is an arithmetic number, because the mean of its divisors is an integer number (103773333438).

Almost surely, 2^311320000311 is an apocalyptic number.

311320000311 is a deficient number, since it is larger than the sum of its proper divisors (103773333441).

311320000311 is a wasteful number, since it uses less digits than its factorization.

311320000311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103773333440.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 311320000311 its reverse (113000023113), we get a palindrome (424320023424).

The spelling of 311320000311 in words is "three hundred eleven billion, three hundred twenty million, three hundred eleven", and thus it is an aban number.