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31132003111012 = 227783000777753
BaseRepresentation
bin1110001010000011110111…
…11111001001000001100100
311002020012010211021000022201
413011001323333021001210
513040031320244023022
6150113502250304244
76362133026152336
oct705017377110144
9132205124230281
1031132003111012
119a13010168021
1235a9710a28084
13144a9735a59ab
14798b22d27456
1538ec3517d127
hex1c507bfc9064

31132003111012 has 6 divisors (see below), whose sum is σ = 54481005444278. Its totient is φ = 15566001555504.

The previous prime is 31132003110977. The next prime is 31132003111031. The reversal of 31132003111012 is 21011130023113.

It can be written as a sum of positive squares in only one way, i.e., 26599847510016 + 4532155600996 = 5157504^2 + 2128886^2 .

It is a super-3 number, since 3×311320031110123 (a number of 41 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3891500388873 + ... + 3891500388880.

Almost surely, 231132003111012 is an apocalyptic number.

It is an amenable number.

31132003111012 is a deficient number, since it is larger than the sum of its proper divisors (23349002333266).

31132003111012 is a wasteful number, since it uses less digits than its factorization.

31132003111012 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7783000777757 (or 7783000777755 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 31132003111012 its reverse (21011130023113), we get a palindrome (52143133134125).

The spelling of 31132003111012 in words is "thirty-one trillion, one hundred thirty-two billion, three million, one hundred eleven thousand, twelve".

Divisors: 1 2 4 7783000777753 15566001555506 31132003111012