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31132021031 = 58675306293
BaseRepresentation
bin11100111111100111…
…001111000100100111
32222100122101112021222
4130333213033010213
51002224244133111
622145111130555
72151323545466
oct347747170447
988318345258
1031132021031
111222623a201
12604a073a5b
132c21a77927
1417149209dd
15c231d77db
hex73f9cf127

31132021031 has 4 divisors (see below), whose sum is σ = 31137333192. Its totient is φ = 31126708872.

The previous prime is 31132020991. The next prime is 31132021049. The reversal of 31132021031 is 13012023113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31132021031 is a prime.

It is a super-2 number, since 2×311320210312 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31132021831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2647280 + ... + 2659013.

It is an arithmetic number, because the mean of its divisors is an integer number (7784333298).

Almost surely, 231132021031 is an apocalyptic number.

31132021031 is a deficient number, since it is larger than the sum of its proper divisors (5312161).

31132021031 is an equidigital number, since it uses as much as digits as its factorization.

31132021031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5312160.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 31132021031 its reverse (13012023113), we get a palindrome (44144044144).

The spelling of 31132021031 in words is "thirty-one billion, one hundred thirty-two million, twenty-one thousand, thirty-one".

Divisors: 1 5867 5306293 31132021031