Base | Representation |
---|---|
bin | 101101010011011001111… |
… | …110110010010110000011 |
3 | 102000121202012022210010001 |
4 | 231103121332302112003 |
5 | 402001330114443230 |
6 | 10342105052220431 |
7 | 440631221411332 |
oct | 55233176622603 |
9 | 12017665283101 |
10 | 3113213437315 |
11 | aa0340907903 |
12 | 423440a6a717 |
13 | 1977619c18b7 |
14 | aa974ba1d19 |
15 | 55ead9e10ca |
hex | 2d4d9fb2583 |
3113213437315 has 24 divisors (see below), whose sum is σ = 3988684438992. Its totient is φ = 2332167559680.
The previous prime is 3113213437309. The next prime is 3113213437343. The reversal of 3113213437315 is 5137343123113.
It is not a de Polignac number, because 3113213437315 - 25 = 3113213437283 is a prime.
It is a super-5 number, since 5×31132134373155 (a number of 64 digits) contains 55555 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5183541 + ... + 5752870.
It is an arithmetic number, because the mean of its divisors is an integer number (166195184958).
Almost surely, 23113213437315 is an apocalyptic number.
3113213437315 is a deficient number, since it is larger than the sum of its proper divisors (875471001677).
3113213437315 is a wasteful number, since it uses less digits than its factorization.
3113213437315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10936647 (or 10936630 counting only the distinct ones).
The product of its digits is 68040, while the sum is 37.
The spelling of 3113213437315 in words is "three trillion, one hundred thirteen billion, two hundred thirteen million, four hundred thirty-seven thousand, three hundred fifteen".
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