Base | Representation |
---|---|
bin | 1110001010000100010011… |
… | …00100110110111101110001 |
3 | 11002020012201201021011121021 |
4 | 13011002021210312331301 |
5 | 13040032302130233241 |
6 | 150113541033055441 |
7 | 6362141465101126 |
oct | 705021144667561 |
9 | 132205651234537 |
10 | 31132231102321 |
11 | 9a13117929298 |
12 | 35a9775257581 |
13 | 144a9ab8b08ab |
14 | 798b4531474d |
15 | 38ec4a1b60d1 |
hex | 1c5089936f71 |
31132231102321 has 8 divisors (see below), whose sum is σ = 31313841068160. Its totient is φ = 30950640158352.
The previous prime is 31132231102307. The next prime is 31132231102373. The reversal of 31132231102321 is 12320113223113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31132231102321 - 25 = 31132231102289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31132231102381) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1465995 + ... + 8025808.
It is an arithmetic number, because the mean of its divisors is an integer number (3914230133520).
Almost surely, 231132231102321 is an apocalyptic number.
It is an amenable number.
31132231102321 is a deficient number, since it is larger than the sum of its proper divisors (181609965839).
31132231102321 is a wasteful number, since it uses less digits than its factorization.
31132231102321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9510935.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 31132231102321 its reverse (12320113223113), we get a palindrome (43452344325434).
The spelling of 31132231102321 in words is "thirty-one trillion, one hundred thirty-two billion, two hundred thirty-one million, one hundred two thousand, three hundred twenty-one".
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