Base | Representation |
---|---|
bin | 1001000011111000101… |
… | …10111001000110000001 |
3 | 1002202120201001220101210 |
4 | 10201330112321012001 |
5 | 20100042422133441 |
6 | 355004214120333 |
7 | 31330620342231 |
oct | 4417426710601 |
9 | 1082521056353 |
10 | 311324021121 |
11 | 110039325a43 |
12 | 504059500a9 |
13 | 23485c14819 |
14 | 110d5079cc1 |
15 | 8171904616 |
hex | 487c5b9181 |
311324021121 has 48 divisors (see below), whose sum is σ = 461209752576. Its totient is φ = 186014744064.
The previous prime is 311324021089. The next prime is 311324021123. The reversal of 311324021121 is 121120423113.
It is not a de Polignac number, because 311324021121 - 25 = 311324021089 is a prime.
It is a super-2 number, since 2×3113240211212 (a number of 24 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (311324021123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4131040 + ... + 4205726.
It is an arithmetic number, because the mean of its divisors is an integer number (9608536512).
Almost surely, 2311324021121 is an apocalyptic number.
It is an amenable number.
311324021121 is a deficient number, since it is larger than the sum of its proper divisors (149885731455).
311324021121 is a wasteful number, since it uses less digits than its factorization.
311324021121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74838 (or 74791 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 311324021121 its reverse (121120423113), we get a palindrome (432444444234).
The spelling of 311324021121 in words is "three hundred eleven billion, three hundred twenty-four million, twenty-one thousand, one hundred twenty-one".
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