311324242414141 has 4 divisors (see below), whose sum is σ = 339626446269984. Its totient is φ = 283022038558300.

The previous prime is 311324242414121. The next prime is 311324242414147. The reversal of 311324242414141 is 141414242423113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311324242414141 - 2⁵ = 311324242414109 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 311324242414141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311324242414147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14151101927905 + ... + 14151101927926.

It is an arithmetic number, because the mean of its divisors is an integer number (84906611567496).

Almost surely, 2^{311324242414141} is an apocalyptic number.

It is an amenable number.

311324242414141 is a deficient number, since it is larger than the sum of its proper divisors (28302203855843).

311324242414141 is a wasteful number, since it uses less digits than its factorization.

311324242414141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28302203855842.

The product of its digits is 73728, while the sum is 37.

Adding to 311324242414141 its reverse (141414242423113), we get a palindrome (452738484837254).

The spelling of 311324242414141 in words is "three hundred eleven trillion, three hundred twenty-four billion, two hundred forty-two million, four hundred fourteen thousand, one hundred forty-one".