3113243014303 has 4 divisors (see below), whose sum is σ = 3113246575480. Its totient is φ = 3113239453128.

The previous prime is 3113243014201. The next prime is 3113243014307. The reversal of 3113243014303 is 3034103423113.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3113243014303 is a prime.

It is a super-2 number, since 2×3113243014303² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113243014307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 531388 + ... + 2551246.

It is an arithmetic number, because the mean of its divisors is an integer number (778311643870).

Almost surely, 2^{3113243014303} is an apocalyptic number.

3113243014303 is a deficient number, since it is larger than the sum of its proper divisors (3561177).

3113243014303 is a wasteful number, since it uses less digits than its factorization.

3113243014303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3561176.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 3113243014303 its reverse (3034103423113), we get a palindrome (6147346437416).

The spelling of 3113243014303 in words is "three trillion, one hundred thirteen billion, two hundred forty-three million, fourteen thousand, three hundred three".