Base | Representation |
---|---|
bin | 100011011001001011101011… |
… | …0011100110010000110011111 |
3 | 1111211022022102220122001201201 |
4 | 1012302113112130302012133 |
5 | 311301214132343220111 |
6 | 3022044224324020331 |
7 | 122401303302131050 |
oct | 10662272634620637 |
9 | 1454268386561651 |
10 | 311324302320031 |
11 | 902199934a7440 |
12 | 2ab0089ab316a7 |
13 | 104939a94848a0 |
14 | 56c4268964727 |
15 | 25ed3d5ed46c1 |
hex | 11b25d673219f |
311324302320031 has 16 divisors (see below), whose sum is σ = 418001860459008. Its totient is φ = 223929568101600.
The previous prime is 311324302320019. The next prime is 311324302320041. The reversal of 311324302320031 is 130023203423113.
It is a cyclic number.
It is not a de Polignac number, because 311324302320031 - 29 = 311324302319519 is a prime.
It is a super-2 number, since 2×3113243023200312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311324302320011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 155506643515 + ... + 155506645516.
It is an arithmetic number, because the mean of its divisors is an integer number (26125116278688).
Almost surely, 2311324302320031 is an apocalyptic number.
311324302320031 is a deficient number, since it is larger than the sum of its proper divisors (106677558138977).
311324302320031 is a wasteful number, since it uses less digits than its factorization.
311324302320031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 311013289062.
The product of its (nonzero) digits is 7776, while the sum is 28.
Adding to 311324302320031 its reverse (130023203423113), we get a palindrome (441347505743144).
The spelling of 311324302320031 in words is "three hundred eleven trillion, three hundred twenty-four billion, three hundred two million, three hundred twenty thousand, thirty-one".
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