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31134013 = 311004323
BaseRepresentation
bin111011011000…
…1000100111101
32011120202211121
41312301010331
530432242023
63031150541
7525430501
oct166610475
964522747
1031134013
1116635499
12a515451
1365b11c1
1441c6301
152aeed5d
hex1db113d

31134013 has 4 divisors (see below), whose sum is σ = 32138368. Its totient is φ = 30129660.

The previous prime is 31134001. The next prime is 31134017. The reversal of 31134013 is 31043113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31043113 = 277112069.

It is a cyclic number.

It is not a de Polignac number, because 31134013 - 25 = 31133981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31134017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502131 + ... + 502192.

It is an arithmetic number, because the mean of its divisors is an integer number (8034592).

Almost surely, 231134013 is an apocalyptic number.

It is an amenable number.

31134013 is a deficient number, since it is larger than the sum of its proper divisors (1004355).

31134013 is a wasteful number, since it uses less digits than its factorization.

31134013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1004354.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 31134013 is about 5579.7861070116. The cubic root of 31134013 is about 314.5900874515.

Adding to 31134013 its reverse (31043113), we get a palindrome (62177126).

It can be divided in two parts, 31 and 134013, that multiplied together give a triangular number (4154403 = T2882).

The spelling of 31134013 in words is "thirty-one million, one hundred thirty-four thousand, thirteen".

Divisors: 1 31 1004323 31134013