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31134341214400 = 2652192006351047
BaseRepresentation
bin1110001010001000001110…
…10110010011000011000000
311002020102011202210222012111
413011010013112103003000
513040101112322330100
6150114530252105104
76362244666542314
oct705040726230300
9132212152728174
1031134341214400
119a13aaaa43776
1235aa063a65194
13144ac56acc318
14798ca5673b44
1538ed205796ba
hex1c51075930c0

31134341214400 has 168 divisors, whose sum is σ = 80647639649280. Its totient is φ = 11797457495040.

The previous prime is 31134341214373. The next prime is 31134341214407. The reversal of 31134341214400 is 441214343113.

It is not an unprimeable number, because it can be changed into a prime (31134341214407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 609889677 + ... + 609940723.

Almost surely, 231134341214400 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31134341214400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (40323819824640).

31134341214400 is an abundant number, since it is smaller than the sum of its proper divisors (49513298434880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31134341214400 is a wasteful number, since it uses less digits than its factorization.

31134341214400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71151 (or 71136 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 31134341214400 its reverse (441214343113), we get a palindrome (31575555557513).

The spelling of 31134341214400 in words is "thirty-one trillion, one hundred thirty-four billion, three hundred forty-one million, two hundred fourteen thousand, four hundred".