Base | Representation |
---|---|
bin | 100011011001010111101001… |
… | …0010001010010000001111111 |
3 | 1111211101202202222010002000112 |
4 | 1012302233102101102001333 |
5 | 311302124301002444444 |
6 | 3022104114421220235 |
7 | 122403203203611524 |
oct | 10662572221220177 |
9 | 1454352688102015 |
10 | 311350001999999 |
11 | 90229881284376 |
12 | 2ab0587186167b |
13 | 10496243947901 |
14 | 56c55c5c0114b |
15 | 25edddc31469e |
hex | 11b2bd245207f |
311350001999999 has 4 divisors (see below), whose sum is σ = 311358198263064. Its totient is φ = 311341805736936.
The previous prime is 311350001999977. The next prime is 311350002000041. The reversal of 311350001999999 is 999999100053113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311350001999999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311350001999969) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4098074552 + ... + 4098150525.
It is an arithmetic number, because the mean of its divisors is an integer number (77839549565766).
Almost surely, 2311350001999999 is an apocalyptic number.
311350001999999 is a deficient number, since it is larger than the sum of its proper divisors (8196263065).
311350001999999 is an equidigital number, since it uses as much as digits as its factorization.
311350001999999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8196263064.
The product of its (nonzero) digits is 23914845, while the sum is 68.
The spelling of 311350001999999 in words is "three hundred eleven trillion, three hundred fifty billion, one million, nine hundred ninety-nine thousand, nine hundred ninety-nine".
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