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311350001999999 = 379878196225077
BaseRepresentation
bin100011011001010111101001…
…0010001010010000001111111
31111211101202202222010002000112
41012302233102101102001333
5311302124301002444444
63022104114421220235
7122403203203611524
oct10662572221220177
91454352688102015
10311350001999999
1190229881284376
122ab0587186167b
1310496243947901
1456c55c5c0114b
1525edddc31469e
hex11b2bd245207f

311350001999999 has 4 divisors (see below), whose sum is σ = 311358198263064. Its totient is φ = 311341805736936.

The previous prime is 311350001999977. The next prime is 311350002000041. The reversal of 311350001999999 is 999999100053113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311350001999999 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311350001999969) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4098074552 + ... + 4098150525.

It is an arithmetic number, because the mean of its divisors is an integer number (77839549565766).

Almost surely, 2311350001999999 is an apocalyptic number.

311350001999999 is a deficient number, since it is larger than the sum of its proper divisors (8196263065).

311350001999999 is an equidigital number, since it uses as much as digits as its factorization.

311350001999999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8196263064.

The product of its (nonzero) digits is 23914845, while the sum is 68.

The spelling of 311350001999999 in words is "three hundred eleven trillion, three hundred fifty billion, one million, nine hundred ninety-nine thousand, nine hundred ninety-nine".

Divisors: 1 37987 8196225077 311350001999999