Base | Representation |
---|---|
bin | 1110001010001010010010… |
… | …00110110100011011111001 |
3 | 11002020112000122202022012120 |
4 | 13011011021012310123321 |
5 | 13040110342234444423 |
6 | 150115231542231453 |
7 | 6362314224114600 |
oct | 705051106643371 |
9 | 132215018668176 |
10 | 31135444453113 |
11 | 9a14516770300 |
12 | 35aa311425589 |
13 | 144b0a15451b0 |
14 | 798d6bdb6a37 |
15 | 38ed8734eee3 |
hex | 1c51491b46f9 |
31135444453113 has 72 divisors (see below), whose sum is σ = 57164122217664. Its totient is φ = 14930083143360.
The previous prime is 31135444453097. The next prime is 31135444453147.
31135444453113 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 31135444453113 - 24 = 31135444453097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31135444455113) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 67094181 + ... + 67556642.
It is an arithmetic number, because the mean of its divisors is an integer number (793946141912).
Almost surely, 231135444453113 is an apocalyptic number.
31135444453113 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
31135444453113 is a deficient number, since it is larger than the sum of its proper divisors (26028677764551).
31135444453113 is a wasteful number, since it uses less digits than its factorization.
31135444453113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134650875 (or 134650857 counting only the distinct ones).
The product of its digits is 518400, while the sum is 42.
It can be divided in two parts, 3113544 and 4453113, that added together give a palindrome (7566657).
The spelling of 31135444453113 in words is "thirty-one trillion, one hundred thirty-five billion, four hundred forty-four million, four hundred fifty-three thousand, one hundred thirteen".
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