311400403001 has 4 divisors (see below), whose sum is σ = 314610716532. Its totient is φ = 308190089472.

The previous prime is 311400402931. The next prime is 311400403009. The reversal of 311400403001 is 100304004113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 100304004113 = 919 ⋅109144727.

It can be written as a sum of positive squares in 2 ways, for example, as 47768473600 + 263631929401 = 218560^2 + 513451^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-311400403001 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (311400403009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1605156620 + ... + 1605156813.

It is an arithmetic number, because the mean of its divisors is an integer number (78652679133).

Almost surely, 2^311400403001 is an apocalyptic number.

It is an amenable number.

311400403001 is a deficient number, since it is larger than the sum of its proper divisors (3210313531).

311400403001 is an equidigital number, since it uses as much as digits as its factorization.

311400403001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3210313530.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 311400403001 its reverse (100304004113), we get a palindrome (411704407114).

The spelling of 311400403001 in words is "three hundred eleven billion, four hundred million, four hundred three thousand, one".