311411314465440 has 192 divisors, whose sum is σ = 1123023686609664. Its totient is φ = 71056366829568.

The previous prime is 311411314465409. The next prime is 311411314465469. The reversal of 311411314465440 is 44564413114113.

It is a Harshad number since it is a multiple of its sum of digits (42).

It is a junction number, because it is equal to n+sod(n) for n = 311411314465392 and 311411314465401.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 78374919 + ... + 82252358.

It is an arithmetic number, because the mean of its divisors is an integer number (5849081701092).

Almost surely, 2^{311411314465440} is an apocalyptic number.

311411314465440 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

311411314465440 is an abundant number, since it is smaller than the sum of its proper divisors (811612372144224).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311411314465440 is a wasteful number, since it uses less digits than its factorization.

311411314465440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 160627879 (or 160627871 counting only the distinct ones).

The product of its (nonzero) digits is 276480, while the sum is 42.

Adding to 311411314465440 its reverse (44564413114113), we get a palindrome (355975727579553).

The spelling of 311411314465440 in words is "three hundred eleven trillion, four hundred eleven billion, three hundred fourteen million, four hundred sixty-five thousand, four hundred forty".