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3114131143 = 25491221707
BaseRepresentation
bin1011100110011101…
…1101111011000111
322001000210020211111
42321213131323013
522334204144033
61233002345451
7140112451354
oct27147357307
98030706744
103114131143
111358933902
1272aabb287
133a8235066
1421783562b
151335da7cd
hexb99ddec7

3114131143 has 4 divisors (see below), whose sum is σ = 3115355400. Its totient is φ = 3112906888.

The previous prime is 3114131131. The next prime is 3114131177. The reversal of 3114131143 is 3411314113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3411314113 = 3901987427.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3114131143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114131183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 608305 + ... + 613402.

It is an arithmetic number, because the mean of its divisors is an integer number (778838850).

Almost surely, 23114131143 is an apocalyptic number.

3114131143 is a deficient number, since it is larger than the sum of its proper divisors (1224257).

3114131143 is a wasteful number, since it uses less digits than its factorization.

3114131143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1224256.

The product of its digits is 432, while the sum is 22.

The square root of 3114131143 is about 55804.4007494033. The cubic root of 3114131143 is about 1460.3119279414.

Adding to 3114131143 its reverse (3411314113), we get a palindrome (6525445256).

The spelling of 3114131143 in words is "three billion, one hundred fourteen million, one hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 2549 1221707 3114131143