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3114145543 = 19163902397
BaseRepresentation
bin1011100110011110…
…0001011100000111
322001000210222120211
42321213201130013
522334210124133
61233002540251
7140112541345
oct27147413407
98030728524
103114145543
111358943703
1272ab07687
133a823b792
1421783a995
151335debcd
hexb99e1707

3114145543 has 4 divisors (see below), whose sum is σ = 3278047960. Its totient is φ = 2950243128.

The previous prime is 3114145487. The next prime is 3114145571. The reversal of 3114145543 is 3455414113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3114145543 - 221 = 3112048391 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114145043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81951180 + ... + 81951217.

It is an arithmetic number, because the mean of its divisors is an integer number (819511990).

Almost surely, 23114145543 is an apocalyptic number.

3114145543 is a deficient number, since it is larger than the sum of its proper divisors (163902417).

3114145543 is a wasteful number, since it uses less digits than its factorization.

3114145543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163902416.

The product of its digits is 14400, while the sum is 31.

The square root of 3114145543 is about 55804.5297713367. The cubic root of 3114145543 is about 1460.3141788057.

Adding to 3114145543 its reverse (3455414113), we get a palindrome (6569559656).

The spelling of 3114145543 in words is "three billion, one hundred fourteen million, one hundred forty-five thousand, five hundred forty-three".

Divisors: 1 19 163902397 3114145543