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3114201340442 = 21557100670221
BaseRepresentation
bin101101010100010100110…
…111010101101000011010
3102000201022001020110102202
4231110110313111220122
5402010341020343232
610342351102330202
7440664545430353
oct55242467255032
912021261213382
103114201340442
11aa07a8519075
12423677889962
1319788b58496a
14aaa2a080d2a
155601a5d3162
hex2d514dd5a1a

3114201340442 has 4 divisors (see below), whose sum is σ = 4671302010666. Its totient is φ = 1557100670220.

The previous prime is 3114201340429. The next prime is 3114201340447. The reversal of 3114201340442 is 2440431024113.

3114201340442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2870344135681 + 243857204761 = 1694209^2 + 493819^2 .

It is not an unprimeable number, because it can be changed into a prime (3114201340447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 778550335109 + ... + 778550335112.

Almost surely, 23114201340442 is an apocalyptic number.

3114201340442 is a deficient number, since it is larger than the sum of its proper divisors (1557100670224).

3114201340442 is a wasteful number, since it uses less digits than its factorization.

3114201340442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1557100670223.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 3114201340442 its reverse (2440431024113), we get a palindrome (5554632364555).

The spelling of 3114201340442 in words is "three trillion, one hundred fourteen billion, two hundred one million, three hundred forty thousand, four hundred forty-two".

Divisors: 1 2 1557100670221 3114201340442