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3114202101 = 31038067367
BaseRepresentation
bin1011100110011110…
…1111001111110101
322001000220212011120
42321213233033311
522334213431401
61233004054153
7140113165263
oct27147571765
98030825146
103114202101
11135898214a
1272ab34359
133a825b44a
14217853433
15133601836
hexb99ef3f5

3114202101 has 4 divisors (see below), whose sum is σ = 4152269472. Its totient is φ = 2076134732.

The previous prime is 3114202097. The next prime is 3114202111. The reversal of 3114202101 is 1012024113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3114202101 - 22 = 3114202097 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114202111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 519033681 + ... + 519033686.

It is an arithmetic number, because the mean of its divisors is an integer number (1038067368).

Almost surely, 23114202101 is an apocalyptic number.

It is an amenable number.

3114202101 is a deficient number, since it is larger than the sum of its proper divisors (1038067371).

3114202101 is a wasteful number, since it uses less digits than its factorization.

3114202101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1038067370.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 3114202101 is about 55805.0365200131. The cubic root of 3114202101 is about 1460.3230193205.

Adding to 3114202101 its reverse (1012024113), we get a palindrome (4126226214).

The spelling of 3114202101 in words is "three billion, one hundred fourteen million, two hundred two thousand, one hundred one".

Divisors: 1 3 1038067367 3114202101