3114241021 has 4 divisors (see below), whose sum is σ = 3114381312. Its totient is φ = 3114100732.

The previous prime is 3114241019. The next prime is 3114241027. The reversal of 3114241021 is 1201424113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1201424113 = 23 ⋅52235831.

It is a cyclic number.

It is not a de Polignac number, because 3114241021 - 2¹ = 3114241019 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3114241021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114241027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28675 + ... + 83968.

It is an arithmetic number, because the mean of its divisors is an integer number (778595328).

Almost surely, 2^3114241021 is an apocalyptic number.

It is an amenable number.

3114241021 is a deficient number, since it is larger than the sum of its proper divisors (140291).

3114241021 is a wasteful number, since it uses less digits than its factorization.

3114241021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 140290.

The product of its (nonzero) digits is 192, while the sum is 19.

The square root of 3114241021 is about 55805.3852329683. The cubic root of 3114241021 is about 1460.3291027980.

Adding to 3114241021 its reverse (1201424113), we get a palindrome (4315665134).

It can be divided in two parts, 311424 and 1021, that added together give a triangular number (312445 = T₇₉₀).

The spelling of 3114241021 in words is "three billion, one hundred fourteen million, two hundred forty-one thousand, twenty-one".