Base | Representation |
---|---|
bin | 1001000100000100101… |
… | …00110000011001101011 |
3 | 1002202211200102200110012 |
4 | 10202002110300121223 |
5 | 20100244033441043 |
6 | 355022151442135 |
7 | 31333244245001 |
oct | 4420224603153 |
9 | 1082750380405 |
10 | 311424124523 |
11 | 11008a888126 |
12 | 5043338634b |
13 | 234a08933c5 |
14 | 11104496a71 |
15 | 817a5c9a18 |
hex | 488253066b |
311424124523 has 4 divisors (see below), whose sum is σ = 312245824440. Its totient is φ = 310602424608.
The previous prime is 311424124519. The next prime is 311424124591. The reversal of 311424124523 is 325421424113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 311424124523 - 22 = 311424124519 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 311424124523.
It is not an unprimeable number, because it can be changed into a prime (311424124223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 410849390 + ... + 410850147.
It is an arithmetic number, because the mean of its divisors is an integer number (78061456110).
Almost surely, 2311424124523 is an apocalyptic number.
311424124523 is a deficient number, since it is larger than the sum of its proper divisors (821699917).
311424124523 is an equidigital number, since it uses as much as digits as its factorization.
311424124523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 821699916.
The product of its digits is 23040, while the sum is 32.
Adding to 311424124523 its reverse (325421424113), we get a palindrome (636845548636).
The spelling of 311424124523 in words is "three hundred eleven billion, four hundred twenty-four million, one hundred twenty-four thousand, five hundred twenty-three".
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