3114300100141 has 4 divisors (see below), whose sum is σ = 3118392479484. Its totient is φ = 3110207720800.

The previous prime is 3114300100139. The next prime is 3114300100147. The reversal of 3114300100141 is 1410010034113.

3114300100141 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1500206079241 + 1614094020900 = 1224829^2 + 1270470^2 .

It is a cyclic number.

It is not a de Polignac number, because 3114300100141 - 2¹ = 3114300100139 is a prime.

It is a super-2 number, since 2×3114300100141² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3114300100147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2046188530 + ... + 2046190051.

It is an arithmetic number, because the mean of its divisors is an integer number (779598119871).

Almost surely, 2^{3114300100141} is an apocalyptic number.

It is an amenable number.

3114300100141 is a deficient number, since it is larger than the sum of its proper divisors (4092379343).

3114300100141 is an equidigital number, since it uses as much as digits as its factorization.

3114300100141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4092379342.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 3114300100141 its reverse (1410010034113), we get a palindrome (4524310134254).

The spelling of 3114300100141 in words is "three trillion, one hundred fourteen billion, three hundred million, one hundred thousand, one hundred forty-one".