311430012401401 has 4 divisors (see below), whose sum is σ = 311431259732992. Its totient is φ = 311428765069812.

The previous prime is 311430012401371. The next prime is 311430012401413. The reversal of 311430012401401 is 104104210034113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311430012401401 - 2¹⁵ = 311430012368633 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311430012401471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 623291205 + ... + 623790658.

It is an arithmetic number, because the mean of its divisors is an integer number (77857814933248).

Almost surely, 2^{311430012401401} is an apocalyptic number.

It is an amenable number.

311430012401401 is a deficient number, since it is larger than the sum of its proper divisors (1247331591).

311430012401401 is a wasteful number, since it uses less digits than its factorization.

311430012401401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1247331590.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 311430012401401 its reverse (104104210034113), we get a palindrome (415534222435514).

The spelling of 311430012401401 in words is "three hundred eleven trillion, four hundred thirty billion, twelve million, four hundred one thousand, four hundred one".