Base | Representation |
---|---|
bin | 100011011001111101000010… |
… | …1001011110111011101001111 |
3 | 1111211200110001222122100101220 |
4 | 1012303322011023313131033 |
5 | 311304433240124112143 |
6 | 3022205035531134423 |
7 | 122412045324040410 |
oct | 10663720513673517 |
9 | 1454613058570356 |
10 | 311430313113423 |
11 | 9025a943865589 |
12 | 2ab193458a4413 |
13 | 104a09a236baba |
14 | 56c9444003807 |
15 | 260103cc89d83 |
hex | 11b3e852f774f |
311430313113423 has 16 divisors (see below), whose sum is σ = 474560741940480. Its totient is φ = 177960079616256.
The previous prime is 311430313113419. The next prime is 311430313113509. The reversal of 311430313113423 is 324311313034113.
It is not a de Polignac number, because 311430313113423 - 22 = 311430313113419 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311430313112423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52282111 + ... + 57933407.
It is an arithmetic number, because the mean of its divisors is an integer number (29660046371280).
Almost surely, 2311430313113423 is an apocalyptic number.
311430313113423 is a deficient number, since it is larger than the sum of its proper divisors (163130428827057).
311430313113423 is a wasteful number, since it uses less digits than its factorization.
311430313113423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8275486.
The product of its (nonzero) digits is 23328, while the sum is 33.
Adding to 311430313113423 its reverse (324311313034113), we get a palindrome (635741626147536).
The spelling of 311430313113423 in words is "three hundred eleven trillion, four hundred thirty billion, three hundred thirteen million, one hundred thirteen thousand, four hundred twenty-three".
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