Base | Representation |
---|---|
bin | 100011011001111101000010… |
… | …1110110100010100100000010 |
3 | 1111211200110002202200200112211 |
4 | 1012303322011312202210002 |
5 | 311304433301010100114 |
6 | 3022205041011012334 |
7 | 122412045521111422 |
oct | 10663720566424402 |
9 | 1454613082620484 |
10 | 311430324300034 |
11 | 9025a94a106215 |
12 | 2ab1934959a0aa |
13 | 104a09a47877b4 |
14 | 56c94456b6482 |
15 | 260103dc496c4 |
hex | 11b3e85da2902 |
311430324300034 has 4 divisors (see below), whose sum is σ = 467145486450054. Its totient is φ = 155715162150016.
The previous prime is 311430324299993. The next prime is 311430324300037. The reversal of 311430324300034 is 430003423034113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 299942461409409 + 11487862890625 = 17318847^2 + 3389375^2 .
It is a junction number, because it is equal to n+sod(n) for n = 311430324299969 and 311430324300005.
It is not an unprimeable number, because it can be changed into a prime (311430324300037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77857581075007 + ... + 77857581075010.
Almost surely, 2311430324300034 is an apocalyptic number.
311430324300034 is a deficient number, since it is larger than the sum of its proper divisors (155715162150020).
311430324300034 is a wasteful number, since it uses less digits than its factorization.
311430324300034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155715162150019.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 311430324300034 its reverse (430003423034113), we get a palindrome (741433747334147).
The spelling of 311430324300034 in words is "three hundred eleven trillion, four hundred thirty billion, three hundred twenty-four million, three hundred thousand, thirty-four".
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