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31143040310111 = 62115014174901
BaseRepresentation
bin1110001010011000011011…
…10110101101101101011111
311002021020122000200211010112
413011030031312231231133
513040221421304410421
6150122525404000235
76363003366616352
oct705141566555537
9132236560624115
1031143040310111
119a177643a3074
1235ab89123007b
13144ba12126032
1479948cb1c299
1539017e11945b
hex1c530ddadb5f

31143040310111 has 4 divisors (see below), whose sum is σ = 31148054491224. Its totient is φ = 31138026129000.

The previous prime is 31143040310099. The next prime is 31143040310113. The reversal of 31143040310111 is 11101304034113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-31143040310111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31143040310113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2507081240 + ... + 2507093661.

It is an arithmetic number, because the mean of its divisors is an integer number (7787013622806).

Almost surely, 231143040310111 is an apocalyptic number.

31143040310111 is a deficient number, since it is larger than the sum of its proper divisors (5014181113).

31143040310111 is an equidigital number, since it uses as much as digits as its factorization.

31143040310111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5014181112.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 31143040310111 its reverse (11101304034113), we get a palindrome (42244344344224).

The spelling of 31143040310111 in words is "thirty-one trillion, one hundred forty-three billion, forty million, three hundred ten thousand, one hundred eleven".

Divisors: 1 6211 5014174901 31143040310111