31143101213113 has 4 divisors (see below), whose sum is σ = 32497149091968. Its totient is φ = 29789053334260.

The previous prime is 31143101213093. The next prime is 31143101213131. The reversal of 31143101213113 is 31131210134113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-31143101213113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31143101211113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 677023939393 + ... + 677023939438.

It is an arithmetic number, because the mean of its divisors is an integer number (8124287272992).

Almost surely, 2^{31143101213113} is an apocalyptic number.

It is an amenable number.

31143101213113 is a deficient number, since it is larger than the sum of its proper divisors (1354047878855).

31143101213113 is a wasteful number, since it uses less digits than its factorization.

31143101213113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1354047878854.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 31143101213113 its reverse (31131210134113), we get a palindrome (62274311347226).

The spelling of 31143101213113 in words is "thirty-one trillion, one hundred forty-three billion, one hundred one million, two hundred thirteen thousand, one hundred thirteen".