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311431032023143 = 2999091038418427
BaseRepresentation
bin100011011001111101011000…
…0000010010010100001100111
31111211200111221002101202010211
41012303322300002102201213
5311304441223144220033
63022205235132000251
7122412102203500204
oct10663726002224147
91454614832352124
10311431032023143
119026018265004a
122ab19506600087
13104a0a8829c276
1456c94b16a0cab
152601080e452cd
hex11b3eb0092867

311431032023143 has 4 divisors (see below), whose sum is σ = 311432070741480. Its totient is φ = 311429993304808.

The previous prime is 311431032023131. The next prime is 311431032023159. The reversal of 311431032023143 is 341320230134113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-311431032023143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311431032023173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 518909305 + ... + 519509122.

It is an arithmetic number, because the mean of its divisors is an integer number (77858017685370).

Almost surely, 2311431032023143 is an apocalyptic number.

311431032023143 is a deficient number, since it is larger than the sum of its proper divisors (1038718337).

311431032023143 is a wasteful number, since it uses less digits than its factorization.

311431032023143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1038718336.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 311431032023143 its reverse (341320230134113), we get a palindrome (652751262157256).

The spelling of 311431032023143 in words is "three hundred eleven trillion, four hundred thirty-one billion, thirty-two million, twenty-three thousand, one hundred forty-three".

Divisors: 1 299909 1038418427 311431032023143