Base | Representation |
---|---|
bin | 1110001010011000100110… |
… | …11101101000111001111010 |
3 | 11002021020212120202002100202 |
4 | 13011030103131220321322 |
5 | 13040222114401300442 |
6 | 150122543004402202 |
7 | 6363005621435303 |
oct | 705142335507172 |
9 | 132236776662322 |
10 | 31143134400122 |
11 | 9a17802518308 |
12 | 35ab8b8846362 |
13 | 144ba2877a7b4 |
14 | 79949b4117aa |
15 | 390187502c32 |
hex | 1c5313768e7a |
31143134400122 has 8 divisors (see below), whose sum is σ = 47055684823956. Its totient is φ = 15457906125472.
The previous prime is 31143134400121. The next prime is 31143134400127. The reversal of 31143134400122 is 22100443134113.
It can be written as a sum of positive squares in 2 ways, for example, as 28500425739241 + 2642708660881 = 5338579^2 + 1625641^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×311431344001222 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (31143134400121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56830536953 + ... + 56830537500.
Almost surely, 231143134400122 is an apocalyptic number.
31143134400122 is a deficient number, since it is larger than the sum of its proper divisors (15912550423834).
31143134400122 is a wasteful number, since it uses less digits than its factorization.
31143134400122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113661074592.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 31143134400122 its reverse (22100443134113), we get a palindrome (53243577534235).
The spelling of 31143134400122 in words is "thirty-one trillion, one hundred forty-three billion, one hundred thirty-four million, four hundred thousand, one hundred twenty-two".
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