Base | Representation |
---|---|
bin | 1110001010011010001111… |
… | …01001111010101111001010 |
3 | 11002021100010121101220101122 |
4 | 13011031013221322233022 |
5 | 13040230413032042442 |
6 | 150123205524315242 |
7 | 6363036413262146 |
oct | 705150751725712 |
9 | 132240117356348 |
10 | 31144010034122 |
11 | 9a18111818077 |
12 | 35abb01b42b22 |
13 | 144bb37cc271b |
14 | 799541828226 |
15 | 3901d9319dd2 |
hex | 1c5347a7abca |
31144010034122 has 16 divisors (see below), whose sum is σ = 46735286747400. Its totient is φ = 15565582437888.
The previous prime is 31144010034119. The next prime is 31144010034139. The reversal of 31144010034122 is 22143001044113.
It can be written as a sum of positive squares in 4 ways, for example, as 19445551103521 + 11698458930601 = 4409711^2 + 3420301^2 .
It is a super-2 number, since 2×311440100341222 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31144010034091 and 31144010034100.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47593538 + ... + 48243474.
Almost surely, 231144010034122 is an apocalyptic number.
31144010034122 is a deficient number, since it is larger than the sum of its proper divisors (15591276713278).
31144010034122 is a wasteful number, since it uses less digits than its factorization.
31144010034122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 659785.
The product of its (nonzero) digits is 2304, while the sum is 26.
Adding to 31144010034122 its reverse (22143001044113), we get a palindrome (53287011078235).
The spelling of 31144010034122 in words is "thirty-one trillion, one hundred forty-four billion, ten million, thirty-four thousand, one hundred twenty-two".
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