Base | Representation |
---|---|
bin | 1110001010011010001111… |
… | …10010010000101011001101 |
3 | 11002021100010202112000102001 |
4 | 13011031013302100223031 |
5 | 13040230414112034013 |
6 | 150123210043232301 |
7 | 6363036441001240 |
oct | 705150762205315 |
9 | 132240122460361 |
10 | 31144012221133 |
11 | 9a18112a81219 |
12 | 35abb02818691 |
13 | 144bb385aa006 |
14 | 799541c37257 |
15 | 3901d95ecddd |
hex | 1c5347c90acd |
31144012221133 has 8 divisors (see below), whose sum is σ = 35620515141120. Its totient is φ = 26674348880400.
The previous prime is 31144012221061. The next prime is 31144012221227. The reversal of 31144012221133 is 33112221044113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31144012221133 - 233 = 31135422286541 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31144012221433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1709885053 + ... + 1709903266.
It is an arithmetic number, because the mean of its divisors is an integer number (4452564392640).
Almost surely, 231144012221133 is an apocalyptic number.
It is an amenable number.
31144012221133 is a deficient number, since it is larger than the sum of its proper divisors (4476502919987).
31144012221133 is a wasteful number, since it uses less digits than its factorization.
31144012221133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3419789627.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 31144012221133 its reverse (33112221044113), we get a palindrome (64256233265246).
The spelling of 31144012221133 in words is "thirty-one trillion, one hundred forty-four billion, twelve million, two hundred twenty-one thousand, one hundred thirty-three".
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