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31144013402 = 215572006701
BaseRepresentation
bin11101000000010100…
…111110111001011010
32222101110221210201212
4131000110332321122
51002240331412102
622150220143122
72151530513615
oct350024767132
988343853655
1031144013402
1112231a90257
126052097aa2
132c243b62c8
14171636317c
15c242a5c52
hex74053ee5a

31144013402 has 4 divisors (see below), whose sum is σ = 46716020106. Its totient is φ = 15572006700.

The previous prime is 31144013399. The next prime is 31144013423. The reversal of 31144013402 is 20431044113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 20144408761 + 10999604641 = 141931^2 + 104879^2 .

It is a super-2 number, since 2×311440134022 (a number of 22 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7786003349 + ... + 7786003352.

Almost surely, 231144013402 is an apocalyptic number.

31144013402 is a deficient number, since it is larger than the sum of its proper divisors (15572006704).

31144013402 is a wasteful number, since it uses less digits than its factorization.

31144013402 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15572006703.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 31144013402 its reverse (20431044113), we get a palindrome (51575057515).

The spelling of 31144013402 in words is "thirty-one billion, one hundred forty-four million, thirteen thousand, four hundred two".

Divisors: 1 2 15572006701 31144013402