Base | Representation |
---|---|
bin | 1110001010011011000111… |
… | …00000111100100000010010 |
3 | 11002021101100011220210100211 |
4 | 13011031203200330200102 |
5 | 13040232342211202424 |
6 | 150123324142434334 |
7 | 6363054120222406 |
oct | 705154340744022 |
9 | 132241304823324 |
10 | 31144477444114 |
11 | 9a18331645121 |
12 | 35b00125929aa |
13 | 144bbb0aa6998 |
14 | 799587939106 |
15 | 390215396b94 |
hex | 1c536383c812 |
31144477444114 has 4 divisors (see below), whose sum is σ = 46716716166174. Its totient is φ = 15572238722056.
The previous prime is 31144477444111. The next prime is 31144477444121. The reversal of 31144477444114 is 41144477444113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 29664198855225 + 1480278588889 = 5446485^2 + 1216667^2 .
It is not an unprimeable number, because it can be changed into a prime (31144477444111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7786119361027 + ... + 7786119361030.
Almost surely, 231144477444114 is an apocalyptic number.
31144477444114 is a deficient number, since it is larger than the sum of its proper divisors (15572238722060).
31144477444114 is a wasteful number, since it uses less digits than its factorization.
31144477444114 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15572238722059.
The product of its digits is 2408448, while the sum is 49.
Subtracting 31144477444114 from its reverse (41144477444113), we obtain a palindrome (9999999999999).
The spelling of 31144477444114 in words is "thirty-one trillion, one hundred forty-four billion, four hundred seventy-seven million, four hundred forty-four thousand, one hundred fourteen".
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