Base | Representation |
---|---|
bin | 1001000100001000000… |
… | …10101110110100110101 |
3 | 1002202220200200100221020 |
4 | 10202010002232310311 |
5 | 20100323424011114 |
6 | 355025101411353 |
7 | 31334044266456 |
oct | 4420402566465 |
9 | 1082820610836 |
10 | 311452953909 |
11 | 1100a5089069 |
12 | 50440b69b59 |
13 | 234a6848606 |
14 | 1110823d12d |
15 | 817cdc1aa9 |
hex | 48840aed35 |
311452953909 has 4 divisors (see below), whose sum is σ = 415270605216. Its totient is φ = 207635302604.
The previous prime is 311452953901. The next prime is 311452953941. The reversal of 311452953909 is 909359254113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 909359254113 = 3 ⋅303119751371.
It is a cyclic number.
It is not a de Polignac number, because 311452953909 - 23 = 311452953901 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311452953901) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51908825649 + ... + 51908825654.
It is an arithmetic number, because the mean of its divisors is an integer number (103817651304).
Almost surely, 2311452953909 is an apocalyptic number.
It is an amenable number.
311452953909 is a deficient number, since it is larger than the sum of its proper divisors (103817651307).
311452953909 is a wasteful number, since it uses less digits than its factorization.
311452953909 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103817651306.
The product of its (nonzero) digits is 1312200, while the sum is 51.
The spelling of 311452953909 in words is "three hundred eleven billion, four hundred fifty-two million, nine hundred fifty-three thousand, nine hundred nine".
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