Base | Representation |
---|---|
bin | 101101010101000000111… |
… | …001111000101001110010 |
3 | 102000210012112112201000000 |
4 | 231111000321320221302 |
5 | 402013344143040212 |
6 | 10342552255010430 |
7 | 441022056612414 |
oct | 55250071705162 |
9 | 12023175481000 |
10 | 3114940205682 |
11 | aa10475a34a8 |
12 | 423843209a16 |
13 | 197978681226 |
14 | aaa9a2549b4 |
15 | 560603d11dc |
hex | 2d540e78a72 |
3114940205682 has 28 divisors (see below), whose sum is σ = 7005410795070. Its totient is φ = 1038313401408.
The previous prime is 3114940205659. The next prime is 3114940205717. The reversal of 3114940205682 is 2865020494113.
3114940205682 is a `hidden beast` number, since 3 + 1 + 1 + 49 + 40 + 2 + 0 + 568 + 2 = 666.
It can be written as a sum of positive squares in only one way, i.e., 2288839177881 + 826101027801 = 1512891^2 + 908901^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 13 ways as a sum of consecutive naturals, for example, 1068222207 + ... + 1068225122.
Almost surely, 23114940205682 is an apocalyptic number.
3114940205682 is an abundant number, since it is smaller than the sum of its proper divisors (3890470589388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3114940205682 is an equidigital number, since it uses as much as digits as its factorization.
3114940205682 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2136447349 (or 2136447334 counting only the distinct ones).
The product of its (nonzero) digits is 414720, while the sum is 45.
Adding to 3114940205682 its reverse (2865020494113), we get a palindrome (5979960699795).
The spelling of 3114940205682 in words is "three trillion, one hundred fourteen billion, nine hundred forty million, two hundred five thousand, six hundred eighty-two".
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