Base | Representation |
---|---|
bin | 101101010101001011110… |
… | …101001110100011000111 |
3 | 102000210200022111202012120 |
4 | 231111023311032203013 |
5 | 402014233111042043 |
6 | 10343022404221023 |
7 | 441026444102364 |
oct | 55251365164307 |
9 | 12023608452176 |
10 | 3115123534023 |
11 | aa1131029826 |
12 | 42389469a773 |
13 | 1979a764c037 |
14 | aaab673746b |
15 | 56071545983 |
hex | 2d54bd4e8c7 |
3115123534023 has 4 divisors (see below), whose sum is σ = 4153498045368. Its totient is φ = 2076749022680.
The previous prime is 3115123533961. The next prime is 3115123534037. The reversal of 3115123534023 is 3204353215113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 3115123534023 - 26 = 3115123533959 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3115123534723) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 519187255668 + ... + 519187255673.
It is an arithmetic number, because the mean of its divisors is an integer number (1038374511342).
Almost surely, 23115123534023 is an apocalyptic number.
3115123534023 is a deficient number, since it is larger than the sum of its proper divisors (1038374511345).
3115123534023 is a wasteful number, since it uses less digits than its factorization.
3115123534023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1038374511344.
The product of its (nonzero) digits is 32400, while the sum is 33.
Adding to 3115123534023 its reverse (3204353215113), we get a palindrome (6319476749136).
The spelling of 3115123534023 in words is "three trillion, one hundred fifteen billion, one hundred twenty-three million, five hundred thirty-four thousand, twenty-three".
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