311521121325431 has 4 divisors (see below), whose sum is σ = 311591777061600. Its totient is φ = 311450465589264.

The previous prime is 311521121325413. The next prime is 311521121325497. The reversal of 311521121325431 is 134523121125113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311521121325431 - 2²² = 311521117131127 is a prime.

It is a super-2 number, since 2×311521121325431² (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311521121325391 and 311521121325400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311521121325731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35327861471 + ... + 35327870288.

It is an arithmetic number, because the mean of its divisors is an integer number (77897944265400).

Almost surely, 2^{311521121325431} is an apocalyptic number.

311521121325431 is a deficient number, since it is larger than the sum of its proper divisors (70655736169).

311521121325431 is an equidigital number, since it uses as much as digits as its factorization.

311521121325431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70655736168.

The product of its digits is 21600, while the sum is 35.

The spelling of 311521121325431 in words is "three hundred eleven trillion, five hundred twenty-one billion, one hundred twenty-one million, three hundred twenty-five thousand, four hundred thirty-one".