3115340021 has 4 divisors (see below), whose sum is σ = 3116299200. Its totient is φ = 3114380844.

The previous prime is 3115340017. The next prime is 3115340029. The reversal of 3115340021 is 1200435113.

3115340021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1200435113 = 23 ⋅52192831.

It is a cyclic number.

It is not a de Polignac number, because 3115340021 - 2² = 3115340017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3115339975 and 3115340002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3115340029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 474701 + ... + 481218.

It is an arithmetic number, because the mean of its divisors is an integer number (779074800).

Almost surely, 2^3115340021 is an apocalyptic number.

It is an amenable number.

3115340021 is a deficient number, since it is larger than the sum of its proper divisors (959179).

3115340021 is an equidigital number, since it uses as much as digits as its factorization.

3115340021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 959178.

The product of its (nonzero) digits is 360, while the sum is 20.

The square root of 3115340021 is about 55815.2310843555. The cubic root of 3115340021 is about 1460.5008635280.

Adding to 3115340021 its reverse (1200435113), we get a palindrome (4315775134).

The spelling of 3115340021 in words is "three billion, one hundred fifteen million, three hundred forty thousand, twenty-one".