Base | Representation |
---|---|
bin | 1110001010101101000110… |
… | …11101100110100101101100 |
3 | 11002022022021121011220100101 |
4 | 13011112203131212211230 |
5 | 13040412134400304312 |
6 | 150132003042040444 |
7 | 6363545431531540 |
oct | 705264335464554 |
9 | 132268247156311 |
10 | 31154140244332 |
11 | 9a2143aa87a26 |
12 | 35b1a6a649124 |
13 | 144ca90970251 |
14 | 799c22da3a20 |
15 | 3905cd848a57 |
hex | 1c55a376696c |
31154140244332 has 12 divisors (see below), whose sum is σ = 62308280488720. Its totient is φ = 13351774390416.
The previous prime is 31154140244321. The next prime is 31154140244351. The reversal of 31154140244332 is 23344204145113.
31154140244332 is an admirable number.
It is a junction number, because it is equal to n+sod(n) for n = 31154140244291 and 31154140244300.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 556323932907 + ... + 556323932962.
Almost surely, 231154140244332 is an apocalyptic number.
It is an amenable number.
31154140244332 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
31154140244332 is a wasteful number, since it uses less digits than its factorization.
31154140244332 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1112647865880 (or 1112647865878 counting only the distinct ones).
The product of its (nonzero) digits is 138240, while the sum is 37.
Adding to 31154140244332 its reverse (23344204145113), we get a palindrome (54498344389445).
The spelling of 31154140244332 in words is "thirty-one trillion, one hundred fifty-four billion, one hundred forty million, two hundred forty-four thousand, three hundred thirty-two".
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