Base | Representation |
---|---|
bin | 100011011110000110110110… |
… | …0001011010111001101010101 |
3 | 1111220201000102210102000220210 |
4 | 1012330031230023113031111 |
5 | 311343311300243420201 |
6 | 3023323200541520033 |
7 | 122501223466163313 |
oct | 10674155413271525 |
9 | 1456630383360823 |
10 | 312001124201301 |
11 | 9045aa2a839407 |
12 | 2ababaa9273019 |
13 | 1051276c999b72 |
14 | 5708d138530b3 |
15 | 2610cea2e61d6 |
hex | 11bc36c2d7355 |
312001124201301 has 8 divisors (see below), whose sum is σ = 416001691874080. Its totient is φ = 208000652998032.
The previous prime is 312001124201281. The next prime is 312001124201309. The reversal of 312001124201301 is 103102421100213.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 312001124201301 - 210 = 312001124200277 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312001124201309) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16199575 + ... + 29772948.
It is an arithmetic number, because the mean of its divisors is an integer number (52000211484260).
Almost surely, 2312001124201301 is an apocalyptic number.
It is an amenable number.
312001124201301 is a deficient number, since it is larger than the sum of its proper divisors (104000567672779).
312001124201301 is a wasteful number, since it uses less digits than its factorization.
312001124201301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48234755.
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 312001124201301 its reverse (103102421100213), we get a palindrome (415103545301514).
The spelling of 312001124201301 in words is "three hundred twelve trillion, one billion, one hundred twenty-four million, two hundred one thousand, three hundred one".
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