Base | Representation |
---|---|
bin | 11101000011101010… |
… | …111111000101101011 |
3 | 2222112101111221220212 |
4 | 131003222333011223 |
5 | 1002344212104003 |
6 | 22155542411335 |
7 | 2153111404403 |
oct | 350352770553 |
9 | 88471457825 |
10 | 31200113003 |
11 | 12260717764 |
12 | 6068a30b4b |
13 | 2c32bc8b37 |
14 | 171d9a7803 |
15 | c29187dd8 |
hex | 743abf16b |
31200113003 has 4 divisors (see below), whose sum is σ = 31246199520. Its totient is φ = 31154026488.
The previous prime is 31200112997. The next prime is 31200113011. The reversal of 31200113003 is 30031100213.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30031100213 = 47 ⋅638959579.
It is a cyclic number.
It is not a de Polignac number, because 31200113003 - 28 = 31200112747 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31200113303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23042243 + ... + 23043596.
It is an arithmetic number, because the mean of its divisors is an integer number (7811549880).
Almost surely, 231200113003 is an apocalyptic number.
31200113003 is a deficient number, since it is larger than the sum of its proper divisors (46086517).
31200113003 is an equidigital number, since it uses as much as digits as its factorization.
31200113003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46086516.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 31200113003 its reverse (30031100213), we get a palindrome (61231213216).
The spelling of 31200113003 in words is "thirty-one billion, two hundred million, one hundred thirteen thousand, three".
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