312001433113201 has 4 divisors (see below), whose sum is σ = 336001543352692. Its totient is φ = 288001322873712.

The previous prime is 312001433113151. The next prime is 312001433113207. The reversal of 312001433113201 is 102311334100213.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 75971183661025 + 236030249452176 = 8716145^2 + 15363276^2 .

It is a cyclic number.

It is not a de Polignac number, because 312001433113201 - 2¹⁵ = 312001433080433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (312001433113207) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12000055119726 + ... + 12000055119751.

It is an arithmetic number, because the mean of its divisors is an integer number (84000385838173).

Almost surely, 2^{312001433113201} is an apocalyptic number.

It is an amenable number.

312001433113201 is a deficient number, since it is larger than the sum of its proper divisors (24000110239491).

312001433113201 is a wasteful number, since it uses less digits than its factorization.

312001433113201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 24000110239490.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 312001433113201 its reverse (102311334100213), we get a palindrome (414312767213414).

The spelling of 312001433113201 in words is "three hundred twelve trillion, one billion, four hundred thirty-three million, one hundred thirteen thousand, two hundred one".