Base | Representation |
---|---|
bin | 100011011110000111010011… |
… | …0111100010011100110011111 |
3 | 1111220201002222111120101112220 |
4 | 1012330032212330103212133 |
5 | 311343320310142010421 |
6 | 3023323442441200423 |
7 | 122501260100235111 |
oct | 10674164674234637 |
9 | 1456632874511486 |
10 | 312002110110111 |
11 | 90460396308283 |
12 | 2abb0123490113 |
13 | 10512899012265 |
14 | 5708da87733b1 |
15 | 2610d56b423c6 |
hex | 11bc3a6f1399f |
312002110110111 has 4 divisors (see below), whose sum is σ = 416002813480152. Its totient is φ = 208001406740072.
The previous prime is 312002110110043. The next prime is 312002110110127. The reversal of 312002110110111 is 111011011200213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 312002110110111 - 229 = 312001573239199 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (312002110110151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52000351685016 + ... + 52000351685021.
It is an arithmetic number, because the mean of its divisors is an integer number (104000703370038).
Almost surely, 2312002110110111 is an apocalyptic number.
312002110110111 is a deficient number, since it is larger than the sum of its proper divisors (104000703370041).
312002110110111 is a wasteful number, since it uses less digits than its factorization.
312002110110111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 104000703370040.
The product of its (nonzero) digits is 12, while the sum is 15.
Adding to 312002110110111 its reverse (111011011200213), we get a palindrome (423013121310324).
The spelling of 312002110110111 in words is "three hundred twelve trillion, two billion, one hundred ten million, one hundred ten thousand, one hundred eleven".
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