Base | Representation |
---|---|
bin | 1110001100000100100110… |
… | …00101011110011011010011 |
3 | 11002110210112000022000122021 |
4 | 13012002103011132123103 |
5 | 13042144333142433433 |
6 | 150205331521352311 |
7 | 6400130411113123 |
oct | 706022305363323 |
9 | 132423460260567 |
10 | 31201110124243 |
11 | 9a3a3532879a4 |
12 | 35bab98798697 |
13 | 1454337a10bb7 |
14 | 79c1db0cac83 |
15 | 39192c19a22d |
hex | 1c609315e6d3 |
31201110124243 has 4 divisors (see below), whose sum is σ = 31201913507920. Its totient is φ = 31200306740568.
The previous prime is 31201110124201. The next prime is 31201110124339. The reversal of 31201110124243 is 34242101110213.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31201110124243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31201110121243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401633580 + ... + 401711257.
It is an arithmetic number, because the mean of its divisors is an integer number (7800478376980).
Almost surely, 231201110124243 is an apocalyptic number.
31201110124243 is a deficient number, since it is larger than the sum of its proper divisors (803383677).
31201110124243 is an equidigital number, since it uses as much as digits as its factorization.
31201110124243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 803383676.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 31201110124243 its reverse (34242101110213), we get a palindrome (65443211234456).
The spelling of 31201110124243 in words is "thirty-one trillion, two hundred one billion, one hundred ten million, one hundred twenty-four thousand, two hundred forty-three".
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