Base | Representation |
---|---|
bin | 100011011110001100011011… |
… | …0101001011100101100100010 |
3 | 1111220202011101011201112100211 |
4 | 1012330120312221130230202 |
5 | 311344010322410122242 |
6 | 3023332502221004334 |
7 | 122502126520361455 |
oct | 10674306651345442 |
9 | 1456664334645324 |
10 | 312013111020322 |
11 | 90465021007a08 |
12 | 2abb22936b36aa |
13 | 10513930197c9a |
14 | 570972d7dd49c |
15 | 261129c811317 |
hex | 11bc636a5cb22 |
312013111020322 has 4 divisors (see below), whose sum is σ = 468019666530486. Its totient is φ = 156006555510160.
The previous prime is 312013111020257. The next prime is 312013111020367. The reversal of 312013111020322 is 223020111310213.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 311673920095521 + 339190924801 = 17654289^2 + 582401^2 .
It is a junction number, because it is equal to n+sod(n) for n = 312013111020293 and 312013111020302.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78003277755079 + ... + 78003277755082.
Almost surely, 2312013111020322 is an apocalyptic number.
312013111020322 is a deficient number, since it is larger than the sum of its proper divisors (156006555510164).
312013111020322 is a wasteful number, since it uses less digits than its factorization.
312013111020322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 156006555510163.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 312013111020322 its reverse (223020111310213), we get a palindrome (535033222330535).
The spelling of 312013111020322 in words is "three hundred twelve trillion, thirteen billion, one hundred eleven million, twenty thousand, three hundred twenty-two".
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