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312013134552155 = 597643326050623
BaseRepresentation
bin100011011110001100011100…
…0000011001101110001011011
31111220202011102211000001222012
41012330120320003031301123
5311344010344421132110
63023332504421220135
7122502130224400421
oct10674307003156133
91456664384001865
10312013134552155
119046503331a803
122abb229b56164b
1310513935016b4a
1457097329a7111
15261129e90d905
hex11bc6380cdc5b

312013134552155 has 8 divisors (see below), whose sum is σ = 378275717766912. Its totient is φ = 247037203438848.

The previous prime is 312013134552113. The next prime is 312013134552199. The reversal of 312013134552155 is 551255431310213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 312013134552155 - 220 = 312013133503579 is a prime.

It is a super-2 number, since 2×3120131345521552 (a number of 30 digits) contains 22 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 321663024827 + ... + 321663025796.

It is an arithmetic number, because the mean of its divisors is an integer number (47284464720864).

Almost surely, 2312013134552155 is an apocalyptic number.

312013134552155 is a deficient number, since it is larger than the sum of its proper divisors (66262583214757).

312013134552155 is an equidigital number, since it uses as much as digits as its factorization.

312013134552155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 643326050725.

The product of its (nonzero) digits is 270000, while the sum is 41.

Adding to 312013134552155 its reverse (551255431310213), we get a palindrome (863268565862368).

The spelling of 312013134552155 in words is "three hundred twelve trillion, thirteen billion, one hundred thirty-four million, five hundred fifty-two thousand, one hundred fifty-five".

Divisors: 1 5 97 485 643326050623 3216630253115 62402626910431 312013134552155