Base | Representation |
---|---|
bin | 1110001100000101001011… |
… | …01011111100110100100111 |
3 | 11002110211022202112010020110 |
4 | 13012002211223330310213 |
5 | 13042201003040400403 |
6 | 150205422510304103 |
7 | 6400141220526231 |
oct | 706024553746447 |
9 | 132424282463213 |
10 | 31201422200103 |
11 | 9a3a4a345a131 |
12 | 35bb0651b8033 |
13 | 145438757937c |
14 | 79c22a725251 |
15 | 391949792103 |
hex | 1c60a5afcd27 |
31201422200103 has 4 divisors (see below), whose sum is σ = 41601896266808. Its totient is φ = 20800948133400.
The previous prime is 31201422200077. The next prime is 31201422200119. The reversal of 31201422200103 is 30100222410213.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 31201422200103 - 216 = 31201422134567 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 31201422200103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31201422200203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5200237033348 + ... + 5200237033353.
It is an arithmetic number, because the mean of its divisors is an integer number (10400474066702).
Almost surely, 231201422200103 is an apocalyptic number.
31201422200103 is a deficient number, since it is larger than the sum of its proper divisors (10400474066705).
31201422200103 is a wasteful number, since it uses less digits than its factorization.
31201422200103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10400474066704.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 31201422200103 its reverse (30100222410213), we get a palindrome (61301644610316).
The spelling of 31201422200103 in words is "thirty-one trillion, two hundred one billion, four hundred twenty-two million, two hundred thousand, one hundred three".
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