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31203040143 = 311945546671
BaseRepresentation
bin11101000011110110…
…001001101110001111
32222112121000200012110
4131003312021232033
51002400434241033
622200125235103
72153145315342
oct350366115617
988477020173
1031203040143
1112262336990
126069a02a93
132c336b2282
14172012a459
15c29565363
hex743d89b8f

31203040143 has 8 divisors (see below), whose sum is σ = 45386240256. Its totient is φ = 18910933400.

The previous prime is 31203040123. The next prime is 31203040213. The reversal of 31203040143 is 34104030213.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 31203040143 - 214 = 31203023759 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31203040123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 472773303 + ... + 472773368.

It is an arithmetic number, because the mean of its divisors is an integer number (5673280032).

Almost surely, 231203040143 is an apocalyptic number.

31203040143 is a gapful number since it is divisible by the number (33) formed by its first and last digit.

31203040143 is a deficient number, since it is larger than the sum of its proper divisors (14183200113).

31203040143 is a wasteful number, since it uses less digits than its factorization.

31203040143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 945546685.

The product of its (nonzero) digits is 864, while the sum is 21.

Adding to 31203040143 its reverse (34104030213), we get a palindrome (65307070356).

The spelling of 31203040143 in words is "thirty-one billion, two hundred three million, forty thousand, one hundred forty-three".

Divisors: 1 3 11 33 945546671 2836640013 10401013381 31203040143